Ohms Law Series-Parallel Circuits Calculation Essay Example for Free

Ohms Law Series-Parallel Circuits Calculation set aboutTo end up the discussion of Series-Parallel Circuits, I would like to post this last one remaining issuing which is about Ohms Law of Series-Parallel Circuits for trustworthys and potentials. I did not even mentioned in my previous topics on how to deal with its genuines and electromotive forces regarding this fictitious character of band connection.Ohms Law in Series-Parallel CircuitsOhms Law in Series-Parallel Circuits CurrentThe kernel menstruation of the series-parallel lap coverings depends on the total resistance offered by the circuit when connected across the potential difference source. The current flow in the completed circuit and it will divide to flow through parallel counterbalancees. In case of parallel branch, the current is inversely proportional to the resistance of the branch that is the greater current flows through the least resistance and vice-versa. Then, the current will then sum up agai n after flowing in different circuit branch which is the aforementioned(prenominal) as the current source or total current.The total circuit current is the akin at each end of a series-parallel circuit, and is equal to the current flow through the voltage source.Ohms Law in Series-Parallel Circuits VoltageThe voltage snitch across a series-parallel circuits also occur the same way as in series and parallel circuits. In series parts of the circuit, the voltage leave out depends on the individual values of the resistors. In parallel parts of the circuit, the voltage across each branch are the same and carries a current depends on the individual values of the resistors.If in case of circuit below, the voltage of the series resistance forming a branch of the parallel circuit will divide the voltage across the parallel circuit. If in case of the single resistance in a parallel branch, the voltage across is the same as the sum of the voltages of the seriesresistances.The sum of the v oltage across R3 and R4 is the same as the voltage across R2.Finally, the sum of the voltage drop across each paths between the two endpoint of the series-parallel circuit is the same as the total voltage applied to the circuit.Lets have a very simple example of this computation for this topic. Considering the circuit below with its given values, lets calculate the total current, current and voltage drop across each resistances.What is the total current, current and voltage across each resistances Here is the simple calculation of the circuit abovea. Calculate first the total resistance of the circuitThe equivalent resistance for R2 and R3 isR2-3 = 25X50/ 25+50 = 16.67 ohmsR total = 30 ohms + 16.67 ohms = 46.67 ohmsb. Calculate the Total Current using Ohms LawI1 = 120V / 46.67 Ohms = 2.57 Amp. Since R1 is in series connection, the total current is the same for that path.c. Calculating the voltage drop for R1VR1 = 2.57 Amp x 30 ohms = 77.1 voltsd. Calculate the voltage drop across R2 and R3.Since the equivalent resistance for R2 and R3 as calculated above is 16.67 ohms, we female genitalia flat calculate the voltage across each branch.VR2 = VR3 = 2.57 Amp x 16.67 ohms = 42. 84 voltse. Finally, we can now calculate the individual current for R2 and R3I2 = VR2 / R2 = 42.84 volts / 25 ohms = 1.71 Amp.I3 = VR3 / R3 = 42.84 volts / 50 ohms = 0.86 Amp.You may also check if the current in each path of the parallel branch are correct by adding its currentsI1 = I2 + I3 = 1.71 Amp + 0.86 Amp = 2.57 Amp. which is the same as calculated above. Therefore, we can say that our answer is correct.